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Q21: Answers – Paper 3 – June 2018
Q21: Answers – Paper 3 – June 2018
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ABCD is a parallelogram.
ABP and QDC are straight lines.
Angle ADP = angle CBQ = 90°
a) Prove that triangle ADP is congruent to triangle CBQ
ABP and QDC are straight lines.
Angle ADP = angle CBQ = 90°
a) Prove that triangle ADP is congruent to triangle CBQ
b) Explain why AQ is parallel to PC.
Question
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21)
21)
ABCD is a parallelogram.
ABP and QDC are straight lines.
Angle ADP = angle CBQ = 90°
a) Prove that triangle ADP is congruent to triangle CBQ
ABP and QDC are straight lines.
Angle ADP = angle CBQ = 90°
a) Prove that triangle ADP is congruent to triangle CBQ
[3 marks]
b) Explain why AQ is parallel to PC.
[2 marks]